Mathématiques

Question

factoriser
=(x-1)(2x+5)+4x^2+20x+25​

1 Réponse

  • Réponse

     

    factoriser (=(x−1)⋅(2⋅x+5)+4⋅x2+20⋅x+25)

    factoriser (=(x-1)⋅(2⋅x+5)+4⋅x2+20⋅x+25)==(x−1)⋅(2⋅x+5)+4⋅x2+20⋅x+25=(x-1)⋅(2⋅x+5)+4⋅x2+20⋅x+25

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