Mathématiques

Question

urgent noté

E=[2+(-2)⁴×3]×(3³-1)

F=3×(1-3)⁵-2²×(3+2)

G=(5-2*3)
          (2-3)⁵

1 Réponse

  • Bonjour


    E=[2+(-2)⁴×3]×(3³-1)

    E = [2 + 16 x 3] x (9 - 1)

    E = (2 + 48) x 8

    E = 50 x 8

    E = 400

    F=3×(1-3)⁵-2²×(3+2)

    F = 3 x (-2)^5 - 4 x (3 + 2)

    F = 3 x (-32) - 4 x (3 + 2)

    F = 3 x (-32) - 4 x 5

    F = -64 - 20

    F = - 84

    G =    
    (5-2*3)
               (2-3)⁵

    G = (5 - 2 x 3)^4  /  (2 - 3)^5

    G = (5 - 6)^4 / (-1)^5

    G = (-1)^4 / (-1)^5

    G = 1/-1

    G = -1

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